Square Root Problem Solving

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Calculators are often used to find the decimal approximation of such a result.

However, a decent approximation can be found without a calculator.

For example, in the problem √2/√3, you would multiply both the top and the bottom by √3.

The result would look like this: √2/√3 = √2/√3 X √3/√3 = √(2X3)/√(3X3) = (√6)/3 And that's your final answer. Try some of these sample square root problems: Here are some additional resources you can use to learn more about square roots: Purple Math.

For example, to solve the problem 2√2 X 3√8, you would multiply the 2 and 3 together first, to get 6, and then you would multiply together the numbers inside of the square root and simplify your answer.

Fitness Essay - Square Root Problem Solving

So the problem would look like this: 2√2 X 3√8 = (2X3)√(2X8) = 6√16 = 6X4 = 24 Dividing by square roots gets a bit more complicated.First, it will be explored how to find integer bounds for a square root.This process can be applied to give an integer approximation to any square root.These square roots can be found by thinking of perfect squares until a match for the radicand is found.For reference, a table of the first ten perfect squares is listed below: The square root operation is not just defined for perfect squares.Rationalizing the denominator involves applying the identity property of multiplication: the fact that multiplying the numerator and denominator by the same number results in an equivalent rational expression.In this case, the number we choose for this is the square root.For these kinds of equations, the positive solution is called the principle square root, while the negative solution is called the negative square root.Some problems will request, "What are the square The square root of a positive integer that is not a perfect square is always an irrational number.However, you may sometimes be asked to manually calculate the square root of some non-perfect square number. & \overline & \overline & \overline & \overline & \underline \ & \underline & & & & & \ 122 & 3 & 00 & & & & \ & \underline & \underline & & & & \ 1244 & & 56 & 00 & & & \ & & \underline & \underline & & & \ 12484 & & 6 & 24 & 00 & & \ & & \underline & \underline & \underline & & \ 124889 & & 1 & 24 & 64 & 00 & \ & & \underline & \underline & \underline & \underline & \ & & & 12 & 23 & 99 & \ \end Checking on a calculator, you find the answer to be correct. When the number of significant figures takes priority, we need a better algorithm.Proposed is the Babylonian method to compute 20.000000000000000000000000000000 10.974999999999999644728632119950 7.264265375854213502293532656040 6.316505985303646042439140728675 6.245402762693970544205512851477 6.244998011514777402908293879591 6.244997998398398308950163482223 The square root of a complex number is somewhat ambiguous.

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